Question
How much does $93 p^2-55 p+4$ exceed $13 p^3-5 p^2+17 p-90$?
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Answer
Required expression is
$93 p^2-55 p+4-\left(13 p^3-5 p^2+17 p-90\right)$
$=93 p^2-55 p+4-13 p^3+5 p^2-17 p+90$
On combining the like terms,
$=93 p^2+5 p^2-55 p-17 p+4+90-13 p^3$
$=98 p^2-72 p+94-13 p^3$
$=-13 p^3+98 p^2-72 p+94$
So,
$93 p^2-55 p+4 \text { is }-13 p^3+9 p^2-72 p+94 \text { exceed from } 13 p^3-5 p^2+17 p-90$
$93 p^2-55 p+4-\left(13 p^3-5 p^2+17 p-90\right)$
$=93 p^2-55 p+4-13 p^3+5 p^2-17 p+90$
On combining the like terms,
$=93 p^2+5 p^2-55 p-17 p+4+90-13 p^3$
$=98 p^2-72 p+94-13 p^3$
$=-13 p^3+98 p^2-72 p+94$
So,
$93 p^2-55 p+4 \text { is }-13 p^3+9 p^2-72 p+94 \text { exceed from } 13 p^3-5 p^2+17 p-90$
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