MCQ
How much is $a^2 - 3a$ greater than $2a^2 + 4a?$
- A$a^2 - 7a$
- B$a^2 + 7a$
- ✓$-a^2 - 7a$
- D$-a^2 + 7a$
✓
Answer
Correct option: C.
$-a^2 - 7a$
Since, $(a^2 - 3a)-(2a^2 + 4a)$
$= a^2 - 3a - 2a^2 - 4a$
$= - a^2 -7a$
So, $a^2-3a$ is greater than $2a^2+4a$ by $-a^2-7a.$
Hence, the correct alternative is option $(c).$
$= a^2 - 3a - 2a^2 - 4a$
$= - a^2 -7a$
So, $a^2-3a$ is greater than $2a^2+4a$ by $-a^2-7a.$
Hence, the correct alternative is option $(c).$
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