How much water should be mixed with $12\ ml$ of alcohol so as to obtain $12 \%$ alcohol solution?
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Concentration of solution $=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times100$
So, Volume of solution $= 100\ ml$
Volume of water = Volume of solution - Volume of solute(alcohol)
Volume of water $= 100 - 12$
Volume of water $= 88\ ml$
So, Volume of solution $= 100\ ml$
Volume of water = Volume of solution - Volume of solute(alcohol)
Volume of water $= 100 - 12$
Volume of water $= 88\ ml$
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