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$2\text{PbO}+4\text{HCl}\xrightarrow{ \ \ \ \ \ \ \ }2\text{PbCl}_2+2\text{H}_2\text{O}$
$\text{PbO}_2+4\text{HCl}\xrightarrow{\ \ \ \ \ \ \ \ }\text{PbCl}_2+\text{Cl}_2+2\text{H}_2\text{O}$
Why do these compounds differ in their reactivity?
$\text{C}_2\text{H}_4(\text{g})+\text{H}_2(\text{g})\overrightarrow{\ \ \ \ \ \ }\ \text{C}_2\text{H}_6(\text{g})$
Calculate enthalpy change for the reaction using the following combustion data:$\text{C}_2\text{H}_4(\text{g})+3\text{O}_2(\text{g})\overrightarrow{\ \ \ \ \ }\ 2\text{CO}_2(\text{g})+2\text{H}_2\text{O(g)};$ $\Delta\text{H}=-1401\text{kJ/ mol}$
$\text{C}_2\text{H}_6(\text{g})+\frac{7}{2}\text{O}_2(\text{g})\overrightarrow{\ \ \ \ \ \ }\ 2\text{CO}_2(\text{g})+3\text{H}_2\text{O(l)};$ $\Delta\text{H}=-1550\text{kJ/ mol}$
$\text{H}_2(\text{g})+\frac{1}{2}\text{O}_2(\text{g})\overrightarrow{\ \ \ \ \ \ }\ \text{H}_2\text{O(l)};$ $\Delta\text{H}=-286.0\text{kJ/ mol}$