Question
How will you distinguish between.
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Answer

1. By reacting with $NaNO _2$ and HCl at the temperature of around 0 to $5^{\circ} C$, Aniline will from diazonium salt. $CH _3 NH _2$ will form methanol and bubbles of $N _2$ gas will come out of the solution.
2. By Hinsberg's reagent, $C _6 H _5 SO _2 Cl \left( CH _3\right)_3 N$ will not react. $\left( CH _3\right)_2 NH$ will form a product which is insoluble in alkali.

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