Question
How will you prepare Propanone (acetone) from Grignard reagent?
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Answer
Grignard reagent (methyl magnesium iodide) reacts with cadmium chloride to give dimethyl cadmium. When acetyl chloride reacts with dimethyl cadmium, propanone (acetone) is obtained.
$2 CH _3 MgI + CdCl _2 \longrightarrow\left( CH _3\right)_2 Cd +2 Mg ( I ) Cl$
$2 CH _3 MgI + CdCl _2 \longrightarrow\left( CH _3\right)_2 Cd +2 Mg ( I ) Cl$
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