MCQ
Hybridisation involves:
  • A
    Addition of an electron pair.
  • B
    Combination and redistribution of atomic orbitals.
  • C
    Removal of an electron pair.
  • D
    Separation of orbitals.

Answer

  1. Combination and redistribution of atomic orbitals.

Explanation:

Hybridization is the concept of mixing atomic orbitals to form new hybrid orbitals.

Atomic orbitals with similar energy combine to give degenerated hybrid orbitals.

The number of combining atomic orbitals is equal to the hybridised orbitals.

They involve redistribution of electrons of combined atomic orbital to hybrid orbitals.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Hypo is used in photography because of it
1 faraday = _________.
For a first order reaction, $A\to  P$, $t_{1/2}$ (half-life) is$10\,days$. The time required for $\frac{{{1^{th}}}}{4}$ conversion of $A$ (in days) is: $(\ln\, 2\, = 0.693,\, \ln\, 3\, = 1.1)$.
Transition metals are often paramagnetic owing to
A solution of a non electrolyte substance containing $1.05\,\, g$ per $100\,\, mL$, was found to be isotonic with $3\%$ glucose solution. The molecular mass of the substance is
The number of unpaired electrons in $C{r^ + }$ will be
A mixture of two completely miscible non-ideal liquids which distil as such without change in its composition at a constant temperature as though it were a pure liquid. This mixture is known as
The number of $P - O - P$ bonds in $H _4 P _2 O _7$, $\left( HPO _3\right)_3$ and $P _4 O _{10}$ are respectively.
The standard reduction potentials at $298 \mathrm{~K}$ for the following half cells are given below :

$\mathrm{Cr}_2 \mathrm{O}_7{ }^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_2 \mathrm{O}, \mathrm{E}^{\circ}=1.33 \mathrm{~V}$

$\mathrm{Fe}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Fe}  \mathrm{E}^{\circ}=-0.04 \mathrm{~V}$

$\mathrm{Ni}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Ni}  \mathrm{E}^{\circ}=-0.25 \mathrm{~V}$

$\mathrm{Ag}^{+}(\mathrm{aq})+\mathrm{e}^{-} \rightarrow \mathrm{Ag} \mathrm{E}^{\circ}=0.80 \mathrm{~V}$

$\mathrm{Au}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Au} \mathrm{E}^{\circ}=1.40 \mathrm{~V}$

Consider the given electrochemical reactions, The number of metal$(s)$ which will be oxidized be $\mathrm{Cr}_2 \mathrm{O}_7{ }^{2-}$, in aqueous solution is. . . . . . 

Consider the plots for the types of reaction. $nA \to  B + C$ These plots respectively corresponds to the reaction orders