- ✓Covalent bond
- BDouble bond
- CCoordinate bond
- DElectrovalent bond
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$\mathrm{Cd}_{(s)}+\mathrm{Hg}_{2} \mathrm{SO}_{4(s)}+\frac{9}{5} \mathrm{H}_{2} \mathrm{O}_{(l)} \rightleftharpoons \mathrm{CdSO}_{4} \cdot \frac{9}{5} \mathrm{H}_{2} \mathrm{O}_{(s)}+2 \mathrm{Hg}_{(l)}$
The value of $\mathrm{E}_{\text {cell }}^{0}$ is $4.315\, \mathrm{~V}$ at $25^{\circ} \mathrm{C}$. If $\Delta \mathrm{H}^{\circ}=-825.2\, \mathrm{~kJ} \,\mathrm{~mol}^{-1}$, the standard entropy change $\Delta \mathrm{S}^{\circ}$ in $\mathrm{J} \,\mathrm{K}^{-1}$ is ........ . (Nearest integer) [Given : Faraday constant $=96487\, \mathrm{C}\, \mathrm{mol}^{-1}$ ]
$C{O_{2(s)}} + {H_{2(g)}} \rightleftharpoons C{O_{(s)}} + {H_2}O(g)\,;\,{K_1}$
$C{O_{2(s)}} + CO(g) \rightleftharpoons C{O_{(s)}} + C{O_2}(g)\,;\,{K_2}$
Calculate the equilibrium for the reaction
$C{O_{2(s)}} + {H_2}(g) \rightleftharpoons CO(g) + {H_2}O(g)\,$