Question
Identify $A$ to $E$ and also explain the reactions involved.
Identify $A$ to $E$ and also explain the reactions involved.
✓
Answer
$A = CuB = Cu(NO_3)_2$
$C = [Cu(NH_3)_4](NO_2)_2$
$D = CO_2$
$E = CaCO_3$
$F = Cu_2[Fe(CN)_6]$
$G = Ca(HCO_3)_2$
$\text{CuCO}_3\rightarrow\text{CuO}+\text{CO}_2\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^{\text{(D)}}$
$\text{CuO}+\text{CuS}\rightarrow\text{Cu}+\text{SO}_2\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^{\text{(A)}}$
$\text{Cu}+\text{4HNO}_3\text{(Conc.)}\rightarrow[\text{Cu(NO}_3)_2+2\text{NO}+2\text{H}_2\text{O}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(B)}$
$\text{Cu}^{2+}+\text{NH}_3\rightarrow[\text{Cu(NH}^3)^4]\\ \ \ \ ^\text{(B)} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(C)}$
$\text{Ca(OH})_2+\text{CO}_2\rightarrow\text{CaCO}_3+\text{H}_2\text{O}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(D)} \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(E)}$
$\text{CaCO}_3+\text{H}_2\text{O}+\text{CO}_2\rightarrow\text{Ca(HCO}_3)_2$
$C = [Cu(NH_3)_4](NO_2)_2$
$D = CO_2$
$E = CaCO_3$
$F = Cu_2[Fe(CN)_6]$
$G = Ca(HCO_3)_2$
$\text{CuCO}_3\rightarrow\text{CuO}+\text{CO}_2\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^{\text{(D)}}$
$\text{CuO}+\text{CuS}\rightarrow\text{Cu}+\text{SO}_2\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^{\text{(A)}}$
$\text{Cu}+\text{4HNO}_3\text{(Conc.)}\rightarrow[\text{Cu(NO}_3)_2+2\text{NO}+2\text{H}_2\text{O}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(B)}$
$\text{Cu}^{2+}+\text{NH}_3\rightarrow[\text{Cu(NH}^3)^4]\\ \ \ \ ^\text{(B)} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(C)}$
$\text{Ca(OH})_2+\text{CO}_2\rightarrow\text{CaCO}_3+\text{H}_2\text{O}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(D)} \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(E)}$
$\text{CaCO}_3+\text{H}_2\text{O}+\text{CO}_2\rightarrow\text{Ca(HCO}_3)_2$
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