MCQ
Identify $B$ formed in the reaction.
$\ce{Cl -\left( CH _2\right)_4 - Cl \xrightarrow{\text { excess } NH _3} A \xrightarrow{ NaOH }B + H _2 O + NaCl}$
$\ce{Cl -\left( CH _2\right)_4 - Cl \xrightarrow{\text { excess } NH _3} A \xrightarrow{ NaOH }B + H _2 O + NaCl}$
- A

- B$ \mathrm{H}_2 \mathrm{~N}-\left(\mathrm{CH}_2\right)_4-\mathrm{NH}_2 $
- C$ {\mathrm{Cl}} N^+ \mathrm{H}_3-\left(\mathrm{CH}_2\right)_4-\stackrel{+}{\mathrm{N}} \mathrm{H}_3 \mathrm{Cl}^{-}$
- D






