MCQ
Identify correct match
- A$S_3O_9 -$ only $p\pi -p\pi $ bond
- ✓$P_4O_{10} -$ Equal number of $\sigma $ and $\pi $ bond
- C$P_4O_6 -$ All $\pi $ bonds are $p\pi -d\pi $ bond
- D$SO_3 -$ both $p\pi -p\pi $ and $p\pi -d\pi $ bond present
Increasing order of acidity is: $H_2Te\, > \,H_2Se \,> \,H_2S \,>\, H_2O$
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$Y$ is
$\mathrm{NaOH}+\mathrm{Cl}_{2} \rightarrow(\mathrm{A})+$ side products
(hot and conc.)
$\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{Cl}_{2} \rightarrow(\mathrm{B})+$ side products
$(dry)$
| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{CH}_3-\mathrm{CHBr}-\mathrm{CD}_3$ on treatment with alc. $\mathrm{KOH}$ gives $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CD}_3$ as a major product. | $(P)$ $E1$ reaction |
| $(B)$ $\mathrm{Ph}-\mathrm{CHBr}-\mathrm{CH}_3$ reacts faster than $\mathrm{Ph}-\mathrm{CHBr}-\mathrm{CD}_3$. | $(Q)$ $E2$ reaction |
| $(C)$ $\mathrm{Ph}-\mathrm{CH}_2-\mathrm{CH}_2 \mathrm{Br}$ on treatment with $\mathrm{C}_2 \mathrm{H}_5 \mathrm{OD} / \mathrm{C}_2 \mathrm{H}_5 \mathrm{O}^{-}$ gives $\mathrm{Ph}-\mathrm{CD}=\mathrm{CH}_2$ as the major product. | $(R)$ $E1$ cb reaction |
| $(D)$ $\mathrm{PhCH}_2 \mathrm{CH}_2 \mathrm{Br}$ and $\mathrm{PhCD}_2 \mathrm{CH}_2 \mathrm{Br}$ react with same rate. | $(S)$ First order reaction |