
- A

- ✓

- C

- D








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$(a)\;\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCH}(\mathrm{OH}) \mathrm{CH}_{3} \stackrel{\mathrm{conc.H}, \mathrm{SO}_{4}}{\longrightarrow}$
$(b)\;\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCH}(\mathrm{Br}) \mathrm{CH}_{3} \stackrel{\text { alc.KOH }}{\longrightarrow}$
$(c)\;\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCH}(\mathrm{Br}) \mathrm{CH}_{3} \xrightarrow[\text { It should be }\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CO}^{-} \mathrm{K}^{+}]{\text { given by } \mathrm{NTA}\left(\mathrm{CH}_{3}\right)_{3} \mathrm{O}^{-} \mathrm{K}^{+}}$
$(d)\;\begin{array}{*{20}{c}}
{{{(C{H_3})}_2}C - C{H_2} - CHO} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{\Delta }$
Which of these reaction(s) will not produce Saytzeff product ?
The above reaction has been studied at $800^{\circ} C$. The related data are given in the table below.
| Reaction serial number | Initial pressure of $H _{2}$ / $kPa$ | Initial Pressure of $NO /$ $kPa$ | Initial rate $\left(\frac{- dp }{ dt }\right) /( kPa / s )$ |
| $1$ | $65.6$ | $40.0$ | $0.135$ |
| $2$ | $65.6$ | $20.1$ | $0.033$ |
| $3$ | $38.6$ | $65.6$ | $0.214$ |
| $4$ | $19.2$ | $65.6$ | $0.106$ |
The order of the reaction with respect to $NO$ is $...........$

The correct statement for product $B$ is. It is