MCQ
Identify product $(P)$
- A
- ✓
- C
- D
✓
Answer
Correct option: B.
b
The decrease of ring strain can provide a driving force strong enough to overcompensete for the conversion of a more stable into less stable cationic centre, the carbooxonium ion $(A)$ rearranges into the carbonium ion $(B)$ because of the release of cyclo butene strain $(2 6 \,kcal/mol)$ in the formation of the cyclopentane (ring strain of about $5\, cal/mol$) cation $B$ stablizer itself by way of another $1,2$ rearrangement. The resulting action $(c)$ has comparebly little ring strain but is an electronically favourable carboxonium ion.
The decrease of ring strain can provide a driving force strong enough to overcompensete for the conversion of a more stable into less stable cationic centre, the carbooxonium ion $(A)$ rearranges into the carbonium ion $(B)$ because of the release of cyclo butene strain $(2 6 \,kcal/mol)$ in the formation of the cyclopentane (ring strain of about $5\, cal/mol$) cation $B$ stablizer itself by way of another $1,2$ rearrangement. The resulting action $(c)$ has comparebly little ring strain but is an electronically favourable carboxonium ion.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In which of the following complexes the CFSE, $\Delta_0$ will be equal to zero?
→Which of the following compounds exhibits optical isomerism
Rearrange the following in the increasing order of acidic strength.
$(i)$ benzoic acid $(ii)\, p$ -methoxybenzoic acid $(iii)\, o$ -methyoxybenzoic acid
→$(i)$ benzoic acid $(ii)\, p$ -methoxybenzoic acid $(iii)\, o$ -methyoxybenzoic acid
The order of reactivity of the given haloalkanes towards nucleophile is
The correct order of ligands arranged in increasing field strength.
Glycerol boils at ${290\,^o}C$ with slight decomposition. Impure glycerine can be purified by
→Correct order of strength of $\pi -$ bond $(s)$ are
→$(I)$ $BO_3^{-3} > CO_3^{-2} > NO_3^-$
$(II)$ $ClO_4^-> SO_4^{-2} > PO_4^{-3}$
$(III)$ $BF_3 > BCl_3 > BBr_3$
$(IV)$ $AlCl_3 > BCl_3$
$(CH_3)_2CHBr$ $\xrightarrow[{(2)\,CuI}]{{(1)\,Li}}\left( A \right)\xrightarrow{{{{\left( {C{H_3}} \right)}_2}CHC{H_2}Br}}B$
→$'B'$ is
The decreasing order of reactivity of the compound given below towards solvolysis under identical condition is
$\,$
→