MCQ
Identify the correct statement for $B _{2} H _{6}$ from those given below.

$(A)$ In $B _{2} H _{6}$, all $B - H$ bonds are equivalent.

$(B)$ In $B _{2} H _{6}$ there are four $3-$centre$-2-$electron bonds.

$(C)$ $B _{2} H _{6}$ is a Lewis acid.

$(D)$ $B _{2} H _{6}$ can be synthesized form both $BF _{3}$ and $NaBH _{4}$.

$(E)$ $B _{2} H _{6}$ is a planar molecule.

Choose the most appropriate answer from the options given below..... .

  • A
    $(A)$ and $(E)$ only
  • B
    $(B), (C)$ and $(E)$ only
  • $(C)$ and $(D)$ only
  • D
    $(C)$ and $(E)$ only

Answer

Correct option: C.
$(C)$ and $(D)$ only
c
$(A)\, (B)$ Two $3$ centre $-2$-electron bonds

$(C)$ $B _{2} H _{6}$ is $e ^{-}$deficient species

$(E)$ $B _{2} H _{6}$ is non - Planar molecule

$(D)$ $BF _{3}+ LiAlH _{4} \rightarrow 2 B _{2} H _{6}+3 LiF +3 AlF _{3}$

$NaBH _{4}+ I _{2} \rightarrow B _{2} H _{6}+2 NaI + H _{2}$

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