MCQ
Identify the correct statement from below:
- AA will be at higher potential.
- BB will be at higher potential.
- CBoth will be at same potential.
- DCan't be said.
✓
Answer
- A will be at higher potential.
Explanation:
Point A have positive charge.
More is the positive charge, more will be the potential. So, A will be at higher potential.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The wavelength of emission line spectrum and absorption line spectrum of a substance are related as
|
(a) Absorption has larger value |
(b) Absorption has smaller value |
|
(c) They are equal |
(d) No relation |
Which of the following particles will experience maximum magnetic force circle when projected with the same velocity perpendicular to a magnetic field?
- Electron
- Proton
- He+
- Li++
Two rays A and B being reflected by a mirror and going as A' and B'. The mirror:
- Is plane.
- Is convex.
- Is concave.
- May be any spherical mirror.
Two radioactive materials 
and 
have decay constants 10λ and λ respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of to that of will be 1/e after a time
|
(a) 1/(10 λ) |
(b) 1/(11 λ) |
(c) 11(10 λ) |
(d) 1(9 λ) |
A body is uniformly rotating about an axis fixed in an inertial frame of reference. Let $\overrightarrow{\text{A}}$ be a unit vector along the axis of rotation and $\overrightarrow{\text{B}}$ be the unit vector along the resultant force on a particle P of the body away from the axis. The value of $\overrightarrow{\text{A}}.\overrightarrow{\text{B}}$ is:
→- 1
- -1
- 0
- None of these.
The focal length of a concave mirror is 10 cm. On placing an object at 10 cm in front of the mirror, its image will be formed:
When the separation between two charges is increased the electric potential energy of the charges.
- Increases.
- Decreases.
- Remains the same.
- May increase or decrease.
Potential difference across the terminals of the battery shown in figure is (r = internal resistance of battery)
|
(a) 8 V |
(b) 10 V |
(c) 6 V |
(d) Zero |
The value of electric field in an electromagnetic wave originating from a point source of light at a distance of 10 meter is $\text{E}=\frac{500\text{Volt}}{\text{m}}$ The electric field at a distance of 5 meter will be.
→The size of the nucleus is approximately :