MCQ
Identify the element which can have highest oxidation numbers
- A$N$
- B$O$
- ✓$Cl$
- D$C$
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(Rounded-off to the nearest integer) $\left[ h =6.63 \times 10^{-34}\, Js , c =3.00 \times 10^{8} \,ms ^{-1}\right.$ $,$ $\left. N _{ A }=6.02 \times 10^{23}\, mol ^{-1}\right]$
$Sn ^{2+}+2 e ^{-} \rightarrow Sn$
$Sn ^{4+}+4 e ^{-} \rightarrow Sn$
The electrode potentials are; $E _{ Sn ^{2+} / Sn }^{\circ}=-0.140\, V$ and $E _{ Sn ^{4+} / Sn }^{\circ}=0.010\, V$. The magnitude of standard electrode potential for $Sn ^{4+} / Sn ^{2+}$ i.e. $E _{ Sn ^{4+} / Sn ^{2+}}^{\circ}$ is $.....\times 10^{-2}\, V$. (Nearest integer)