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- Abutylamine
- Bbutanamide
- C$\alpha$-bromobutanoic acid
- ✓propylamine
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- Step$-l$ is $\mathrm{S}_{\mathrm{N}}$ reaction with $\stackrel{\ominus}{\mathrm{C}} \mathrm{N}$ nucleophile.
- Step$-Il$ will give amide.
- Step$-III$ is Hoffmann bromamide degradation reaction.
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$3,4,5-$Tribromoaniline $\underset{\text{(ii) }{{H}_{3}}P{{O}_{2}}}{\mathop{\xrightarrow{\text{(i) diazotization}}}}\,\,?$
( $\rho_{ Ni }$ (density of Nickel) is $10 \,gmL ^{-1}$, Molar mass of Nickel is $60\,gmol ^{-1} F =96500\,C\,mol ^{-1}$ )
Statement $(I)$ : The $\mathrm{NH}_2$ group in Aniline is ortho and para directing and a powerful activating group.
Statement $(II)$ : Aniline does not undergo FriedelCraft's reaction (alkylation and acylation).
In the light of the above statements, choose the most appropriate answer from the options given below :