MCQ
Identify the optically active compounds from the following:
- A[Co(en)3]3+
- BTrans– [Co(en)2Cl2]+
- CCis– [Co(en)2Cl2]+
- D[Cr(NH3)5Cl]
✓
Answer
- [Co(en)3]3+
- Cis– [Co(en)2Cl2]+
Explanation:
(a, c) [Co(en)3]3+ and cis [Co(en)2Cl2]2+ are optically active compounds because their mirror images are non-superimposable isomer.
Non-supermposable isomers of [Co(en)3]3+
Non-superimosable isomers of [Co(en)2Cl2]+
Hence, (a) and (c) are correct choices.
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Using the data given in find out in which option the order of reducing power is correct.
$\text{E}^\ominus_{\text{cr}_2\text{O}^{2-}_7/\text{cr}^{3+}}=1.33\text{V}\ \ \ \text{E}^\ominus_{\text{Cl}_2/\text{Cl}^-}=1.36\text{V}$
$\text{E}^\ominus_{\text{MnO}^-_4/\text{Mn}^{2+}}=1.51\text{V}\ \ \ \ \text{E}^\ominus_{\text{Cr}^{3+}/\text{Cr}}=-0.74\text{V}$
→$\text{E}^\ominus_{\text{cr}_2\text{O}^{2-}_7/\text{cr}^{3+}}=1.33\text{V}\ \ \ \text{E}^\ominus_{\text{Cl}_2/\text{Cl}^-}=1.36\text{V}$
$\text{E}^\ominus_{\text{MnO}^-_4/\text{Mn}^{2+}}=1.51\text{V}\ \ \ \ \text{E}^\ominus_{\text{Cr}^{3+}/\text{Cr}}=-0.74\text{V}$