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If the distance between two consecutive base pairs is $0.34\, nm$ and the total number of base pairs of a $DNA$ double helix in a typical mammalian cell is $6.6 \times 10^{9}$ $bp,$ then the length of the $DNA$ is approximately
$A$ : Triplet genetic code can be confirmed by frame shift mutations.
$R$ : Frame shifting involves the change in protein product coded by triplet codons