MCQ
If $(1 - i)x + (1 + i)y = 1 - 3i,$ then $(x,y) = $
- ✓$(2, - 1)$
- B$( - 2,\,1)$
- C$( - 2, - 1)$
- D$(2, 1)$
$ \Rightarrow $ $(x + y) + i\,( - x + y) = 1 - 3\,i$
Equating real and imaginary parts, we get $x + y = 1$and $ - x + y = - 3$; $\therefore $ $x = 2,y = - 1$.
Thus point is $(2,\, - 1)$.
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