Question
If $10^\text{n} + 3 \times 4^{\text{n}+2}+\lambda$ is divisible by 9 for all $\text{n}\in\text{N},$ then the least positive integer value of $\lambda$ is
- 5
- 3
- 7
- 1
Solution:
Given,
$10\text{n }+3\times^{\text{n}+2}+\lambda$ is divisible by 9,
$\text{P}(1)=10^1+3\times4^{1+2}+\lambda$ is exactly divisible by 9 then the value of $\lambda$ is 5.
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$\frac13$
$\frac23$
$\frac14$
$\frac34.$
The value of $(\text{z}+3)(\bar{\text{z}}+3)$ is equivalent to: