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STD 11 - 7. binomial theoram — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 7. binomial theoram4 Marks
MCQ
If $(11)^{27} + (21)^{27}$ when divided by $16$ leaves the remainder
  • ✓
    $0$
  • B
    $1$
  • C
    $2$
  • D
    $14$
✓

Answer

Correct option: A.
$0$
a
$a^n + b^n = (a + b) (Q (a, b) )$ if $n$ is odd

alternatively :

interpret from $(16 - 5)^{27} + (16 + 5)^{27}$

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