Question
If $1176=2^\text{a}\times3^\text{b}\times7^\text{c},$ find $a, b$ and $c.$
✓
Answer
Given that $2, 3$ and $7$ are factors of $1176.$
Taking out the $LCM$ of $1176$,
we get $2^3\times3^1\times7^2=2^\text{a}\times3^\text{b}\times7^\text{c}$
By commparing, we get
$\text{a}=3,\ \text{b}=1$ and $\text{c}=2.$
Taking out the $LCM$ of $1176$,
we get $2^3\times3^1\times7^2=2^\text{a}\times3^\text{b}\times7^\text{c}$
By commparing, we get
$\text{a}=3,\ \text{b}=1$ and $\text{c}=2.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Simplify: $2 ^ { \frac { 2 } { 3 } } \cdot 2 ^ { \frac { 1 } { 3 } }$
→Verify whether the indicated numbers are zeros of the polynomials corresponding to them in the following case: $f(x)=x^2, x=0$
→ Examine whether the following number are rational or irrational: $\sqrt{8}+4\sqrt{32}-6\sqrt{2}$
→Factorise:
$2 x^2+11 x-21$
→$2 x^2+11 x-21$
Factorise:
$24 x^2-41 x+12$
→$24 x^2-41 x+12$
In the we have $AB = BC, BX = BY$. Show that $AX = CY.$
→The mean of $31$ results is $60$. If the mean of the first $16$ results is $58$ and that of the last $16$ results is $62$, find the $16^{\text {th}}$ result.
→Factorise:
$4 x^2+9 y^2+16 z^2+12 x y-24 y z-16 x z$
→$4 x^2+9 y^2+16 z^2+12 x y-24 y z-16 x z$
Factorise:
$4 a^2-4 b^2+4 a+1$
→$4 a^2-4 b^2+4 a+1$
The mean of marks scored by $100$ students was found to be $40$. Later on, it was discovered that a score of $53$ was misread as $83$. Find the correct mean.
→