MCQ
If $12$ identical balls are to be placed randomly in $3$ identical boxes, then the probability that one of the boxes contains exactly $3$ balls is
- A$\frac{4}{{19}}$
- B$\frac{{55}}{3}{\left( {\frac{2}{3}} \right)^{11}}$
- ✓$\frac{{\left( {428} \right){}^{12}{C_3}}}{{{3^{11}}}}$
- D$\frac{5}{{19}}$