Question
If $\frac{1}{8 !}+\frac{1}{9 !}=\frac{x}{10 !}$, find x.

Answer

Given,$\frac{1}{8 !}+\frac{1}{9 \times 8 !}=\frac{x}{10 \times 9 \times 8 !}$
Therefore 1 + $\frac{1}{9}=\frac{x}{10 \times 9}$ or $\frac{10}{9}=\frac{x}{10 \times 9}$
Thus, x = 100

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