Question
If $2 \log x + 1 = 40,$ find$: x$

Answer

$2 \log x+1=40$
$\Rightarrow 2 \log x=39$
$\Rightarrow \log x^2=39$
$\Rightarrow x^2=10^{39}$
$\Rightarrow x=10^{\frac{39}{2}}$

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