Question
If $2 \log x + 1 =\log 360,$ find$: x$
✓
Answer
$x$
$2 \log x+1=\log 360$
$\Rightarrow \log x^2+\log 10=\log 360$
$\Rightarrow \log \left(10 x^2\right)=\log 360$
$\Rightarrow 10 x^2=360$
$\Rightarrow x^2=\frac{360}{10}=36$
$\Rightarrow x=\sqrt{36}= \pm 6$
As negative value is rejected,
$\therefore x =6 \text {. }$
$2 \log x+1=\log 360$
$\Rightarrow \log x^2+\log 10=\log 360$
$\Rightarrow \log \left(10 x^2\right)=\log 360$
$\Rightarrow 10 x^2=360$
$\Rightarrow x^2=\frac{360}{10}=36$
$\Rightarrow x=\sqrt{36}= \pm 6$
As negative value is rejected,
$\therefore x =6 \text {. }$
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