MCQ
If $(2021)^{3762}$ is divided by $17$, then the remainder is ........
- A$9$
- B$12$
- ✓$4$
- D$8$
$=17 k _{2}+2^{3762}($ as $2023=17 \times 17 \times 9)$
$=17 k _{2}+4 \times 16^{940}$
$=17 k _{2}+4 \times(17-1)^{940}$
$=17 k _{2}+4\left(17 k _{3}+1\right)$
$=17 k +4 \Rightarrow$ remainder $=4$
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