Exponents Of Real Numbers — Maths STD 9 — Question

We have to find the value of $3^x$ provided $\left(2^3\right)^2=4^x$
So,
$2^{3 \times 2}=2^{2 x}$
$2^6=2^{2 x}$
By equating the exponents we get
$6=2 x$
$\frac{6}{2}=x$
$3=x$
By substituting in $3^{\mathrm{x}}$ we get
$3^x=3^3$
$=27$
The value of $3^{\mathrm{x}}$ is $27$
Hence the correct choice is $d$.