If ( 2^ n + 1 ) ^m ( 2^ 2n ) 2^n ( 2^ m + 1 ) ^n 2^ 2m = 1, then … - Vidyadip

MCQ

If ${{{{({2^{n + 1}})}^m}({2^{2n}}){2^n}} \over {{{({2^{m + 1}})}^n}{2^{2m}}}} = 1,$ then $m =$

A
$0$
B
$1$
C
$n$
✓
$2n$

✓

Answer

Correct option: D.

$2n$

d
(d) ${2^{m(n + 1) + 2n + n}} = {2^{(m + 1)n + 2m}}$

$ \Rightarrow $$mn + m + 3n = mn + 2m + n$$ \Rightarrow $$m = 2n$.

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