Question
If $2\tan\alpha=3\tan\beta,$ prove that $\tan(\alpha-\beta)=\frac{\sin2\beta}{5-\cos2\beta}$
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Marks
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$0$ | $1$ | $2$ | $3$ | $4$ | $5$ |
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Frequency
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$x - 2$ | $x$ | $x^2$ | $(x + 1)^2$ | $2x$ | $x + 1$ |