If 2X - [ * 20 c 1&2 7&4 ] = [ * 20 c 3&2 0& - 2 ], then X is equ… - Vidyadip

MCQ

If $2X - \left[ {\begin{array}{*{20}{c}}1&2\\7&4\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}3&2\\0&{ - 2}\end{array}} \right]$, then $X$ is equal to

A
$\left[ {\begin{array}{*{20}{c}}2&2\\7&4\end{array}} \right]$
B
$\left[ {\begin{array}{*{20}{c}}1&2\\{7/2}&2\end{array}} \right]$
✓
$\left[ {\begin{array}{*{20}{c}}2&2\\{7/2}&1\end{array}} \right]$
D
None of these

✓

Answer

Correct option: C.

$\left[ {\begin{array}{*{20}{c}}2&2\\{7/2}&1\end{array}} \right]$

c
(c) $2X - \left[ {\begin{array}{*{20}{c}}1&2\\7&4\end{array}} \right]\, = \,\left[ {\begin{array}{*{20}{c}}3&2\\0&{ - 2}\end{array}} \right]$

==> $2X = \left[ {\begin{array}{*{20}{c}}3&2\\0&{ - 2}\end{array}} \right] + \left[ {\begin{array}{*{20}{c}}1&2\\7&4\end{array}} \right]$

==> $2X = \left[ {\begin{array}{*{20}{c}}4&4\\7&2\end{array}} \right]$

==> $X = \left[ {\begin{array}{*{20}{c}}2&2\\{7/2}&1\end{array}} \right]$.

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