Question
If $3 x^2 y+3 x y^2=0$ then $\frac{d y}{d x}=$..........

Answer

$-1$
Hint:
$
\begin{aligned}
& 3 x^2 y+3 x y^2=0 \\
& \therefore 3 x y(x+y)=0 \\
& \therefore x+y=0 \\
& \therefore y=-x \\
& \therefore \frac{d y}{d x}=-1
\end{aligned}
$

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