Question
If 3A = 4B = 6C; find A: B: C.
✓
Answer
3A = 4B = 6C
$3 A=4 B \Rightarrow \frac{A}{B}=\frac{4}{3}$
This means, A:B=4:3
$4 B=6 C \Rightarrow \frac{B}{C}=\frac{6}{4}=\frac{3}{2}$
=>B:C=3:2
The value of B in 4:3 is equal to the value of B in 3:2
Hence A : B : C = 4 : 3 : 2
$3 A=4 B \Rightarrow \frac{A}{B}=\frac{4}{3}$
This means, A:B=4:3
$4 B=6 C \Rightarrow \frac{B}{C}=\frac{6}{4}=\frac{3}{2}$
=>B:C=3:2
The value of B in 4:3 is equal to the value of B in 3:2
Hence A : B : C = 4 : 3 : 2
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In ABCD is a cyclic quadrilateral in which ∠ DAC = 27° , ∠ DBA = 50° and ∠ ADB = 33°. Calculate ∠ CAB.
If two coins are tossed once, what is the probability of getting: at least one head.
A card is drawn from a pack of 52 cards. Find the probability that the card drawn is : a red card
Solve : 1 ≥ 15 – 7x > 2x – 27, x ∈ N
Prove.$\sqrt{\frac{1-\sin A}{1+\sin A}}=\frac{\cos A}{1+\sin A}$
→The volume of a sphere is $38808 cm ^3$ find its diameter and the surface area.
→Prove that $\frac{\tan \theta}{\cot \left(90^{\circ}-\theta\right)}+\frac{\sec \left(90^{\circ}-\theta\right) \sin \left(90^{\circ}-\theta\right)}{\cos \theta \cdot \cos e c} \theta=2$.
→Find the co-ordinates of the centroid of a triangle ABC whose vertices are: $A(-1, 3), B(1, -1)$ and $C(5, 1)$
→If q is the mean proportional between p and r, show that: pqr $(p + q + r)^3 = (pq + qr + rp)^3$
→Find the equations of a line passing through the point $(2, 3)$ and having the $x\ –$ interecpt of $4$ units.
→