MCQ
If – 3x + 17 < – 13, then:
  • $\text{x}\in(10,\infty)$
  • B
    $\text{x}\in\big[10,\infty)$
  • C
    $\text{x}\in(-\infty,10\big]$
  • D
    $\text{x}\in\big[-10,10)$

Answer

Correct option: A.
$\text{x}\in(10,\infty)$
Given,
-3x + 17 < -13
Subtracting 17 from both sides,
-3x + 17 – 17 < -13 – 17
$\Rightarrow$ -3x < -30
$\Rightarrow$ x > 10 (since the division by negative number inverts the inequality sign)
$\Rightarrow\text{x}\in(10,\infty)$

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