MCQ
If $− 3x + 17 < -13,$ then:
  • $\text{x}\in(10,\infty)$
  • B
    $\text{x}\in[10,\infty)$
  • C
    $\text{x}\in(-\infty,10]$
  • D
    $\text{x}\in[-10,10)$

Answer

Correct option: A.
$\text{x}\in(10,\infty)$
$− 3x + 17 < −13$
Subtracting $17$ on both sides, we get
$\Rightarrow −3x + 17 − 17 < −13 − 17$
$\Rightarrow −3x < − 30$
Dividing $−3$ on both sides, we get
$\Rightarrow\frac{-3\text{x}}{-3}>\frac{-30}{-3}$
$\Rightarrow\text{x}>10$
$\Rightarrow\text{x}\in(10,\infty)$

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