MCQ
If ${{3x + a} \over {{x^2} - 3x + 2}} = {A \over {(x - 2)}} - {{10} \over {x - 1}}$, then
- A$a = 7$
- B$a = - 7$
- C$A = 13$
- ✓$(a)$ and $(c)$ both
==> $(3x + a) = A(x - 1) - 10(x - 2)$
==> $3 = A - 10$, $a = - A + 20$
(On equating coefficients of $x$ and constant term)
==> $A = 13, a = 7.$
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