MCQ
If ${{3x + a} \over {{x^2} - 3x + 2}} = {A \over {(x - 2)}} - {{10} \over {x - 1}}$, then
  • A
    $a = 7$
  • B
    $a = - 7$
  • C
    $A = 13$
  • $(a)$ and $(c)$ both

Answer

Correct option: D.
$(a)$ and $(c)$ both
d
(d) ${{3x + a} \over {{x^2} - 3x + 2}} = {A \over {(x - 2)}} - {{10} \over {(x - 1)}}$

==> $(3x + a) = A(x - 1) - 10(x - 2)$

==> $3 = A - 10$, $a = - A + 20$

(On equating coefficients of $x$ and constant term)

==> $A = 13, a = 7.$

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