MCQ
If $4 \tan \beta=3$, then $\frac{4 \sin \beta-3 \cos \beta}{4 \sin \beta+3 \cos \beta}=$
- ✓$0$
- B$1 / 3$
- C$2 / 3$
- D$7 / 25$
✓
Answer
Correct option: A.
$0$
A
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