MCQ
If $4^{2\text{x}}=\frac{1}{32},$ then the value of x is:
- A$\frac{5}{4}$
- ✓$-\frac{5}{4}$
- C$\frac{3}{4}$
- D$-\frac{5}{2}$
$4^{2\text{x}}=\frac{1}{32}$
$\Rightarrow(2^2)^{2\text{x}}=\frac{1}{2^5}$
$\Rightarrow2^{4\text{x}}2^{-5}$
$\Rightarrow4\text{x}=-5$
$\text{x}=\frac{-5}{4}$
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