MCQ
If $4{\sin ^{ - 1}}x + {\cos ^{ - 1}}x = \pi ,$ then $x$ is equal to
- A$0$
- ✓$\frac{1}{2}$
- C$ - \frac{{\sqrt 3 }}{2}$
- D$\frac{1}{{\sqrt 2 }}$
==> $3{\sin ^{ - 1}}x + {\sin ^{ - 1}}x + {\cos ^{ - 1}}x = \pi $
==> $3{\sin ^{ - 1}}x = \pi - \frac{\pi }{2} = \frac{\pi }{2}$
==> ${\sin ^{ - 1}}x = \pi /6$
==> $x = \sin \frac{\pi }{6} = \frac{1}{2}$.
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