MCQ
If $4{\sin ^4}x + {\cos ^4}x = 1,$ then $x =$
  • $n\pi $
  • B
    $n\pi \pm {\sin ^{ - 1}}\frac{2}{5}$
  • C
    $n\pi + \frac{\pi }{6}$
  • D
    None of these

Answer

Correct option: A.
$n\pi $
a
(a) The given equation can be put in the form

$4{\sin ^4}x = 1 - {\cos ^4}x = (1 - {\cos ^2}x)\,(1 + {\cos ^2}x)$

$ \Rightarrow $ ${\sin ^2}x[4{\sin ^2}x - 1 - (1 - {\sin ^2}x)] = 0$

$ \Rightarrow $${\sin ^2}x[5{\sin ^2}x - 2] = 0$

$ \Rightarrow $$\sin x = 0$ or $\sin x = \pm \sqrt {2/5} $.

Hence $x = n\pi $ is the required answer.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

$\mathop {\lim }\limits_{x \to 0} \frac{{\sin x + \log (1 - x)}}{{{x^2}}}$ is equal to
Let $w _1$ be the point obtained by the rotation of $z_1=5+4 i$ about the origin through a right angle in the anticlockwise direction, and $w_2$ be the point obtained by the rotation of $z_2=3+5 i$ about the origin through a right angle in the clockwise direction. Then the principal argument of $w _1- w _2$ is equal to $...........$.
The derivative of $y = (1 - x)\,(2 - x)....(n - x)$ at $x = 1$ is equal to
Let $\alpha >0$ be a real number. Then the limit $\lim _{x \rightarrow 2} \frac{a^x+a^{3-x}-\left(a^2+a\right)}{a^{3-x}-a^{x / 2}}$ is
If $n(A) = 3$ and $n(B) = 6$ and $A \subseteq B$. Then the number of elements in $A \cap B$ is equal to
The equation of the circle having the lines $y^2 - 2y + 4x - 2xy = 0$ as its normals $\&$ passing through the point $(2 , 1)$ is :
The general solution of differential equation $\frac{{dy}}{{dx}} + \frac{{y\ln y}}{x} = \frac{{y{{(\ln y)}^2}}}{{{x^2}}}$ is (where $C$ is an arbitrary constant)
Number of solutions of equation $sgn(sin x) = sin^2x + 2sinx + sgn(sin^2x)$ in $\left[ { - \frac{{5\pi }}{2},\frac{{7\pi }}{2}} \right]$  is

(where $sgn(.)$ denotes signum function) -

The sides of a triangle are distinct positive integers in an arithmetic progression. If the smallest side is $10$, the number of such triangles is
Let $f:[-1,1] \rightarrow R$ be defined as $f(x)=a x^{2}+b x+c$ for all $x \in[-1,1],$ where $a , b , c \in R$ such that $f (-1)=2, f ^{\prime}(-1)=1$ and for $x \in(-1,1)$ the maximum value of $f ^{\prime \prime}( x )$ is $\frac{1}{2} .$ If $f ( x ) \leq \alpha$ , $x \in[-1,1],$ then the least value of $\alpha$ is equal to ...... .