MCQ
If $a = 2i + 4j + 2k$ and $b = 8i - 3j + \lambda k$ and $a\, \bot \,b,$ then value of $\lambda $ will be
- A$2$
- B$-1$
- ✓$-2$
- D$1$
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The solution of the differential equation $\frac{\text{dy}}{\text{dx}}+\frac{2\text{xy}}{1+\text{x}^2}=\frac{1}{(1+\text{x}^2)^2}$ is:
$\text{y}(1+\text{x}^2)=\text{C}+\tan^{-1}\text{x}$
$\frac{\text{y}}{1+\text{x}^2}=\text{C}+\tan^{-1}\text{x}$
$\text{y}\log(1+\text{x}^2)=\text{C}+\tan^{-1}\text{x}$
$\text{y}(1+\text{x}^2)=\text{C}+\sin^{-1}\text{x}$