Question
If $a=3$ and $b=-2$, find the values of:
$a+b^{a b}$
$a+b^{a b}$
✓
Answer
We have, $a^b+b^a=(3+(-2))^{3(-2)}$
$=(3-2)^{-6}$
$=(1)^{-6}$
$=1$
$=(3-2)^{-6}$
$=(1)^{-6}$
$=1$
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