MCQ
If a = 3 and b = 2 , then $(3 a-4 b)^{b-a} \div(4 a-3 b)^{2 b-a}$ is equal to
- A1
- B6
- ✓$1 / 6$
- D$2 / 3$
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$\frac{2}{5}$
$\frac{5}{3}$
$\frac{3}{5}$
$\frac{2}{7}$