MCQ
If a = 3 and b = 2 , then $(3 a-4 b)^{b-a} \div(4 a-3 b)^{2 b-a}$ is equal to
  • A
    1
  • B
    6
  • $1 / 6$
  • D
    $2 / 3$

Answer

Correct option: C.
$1 / 6$
(c)
For a = 3 and b = 2 we find that
$(3 a-4 b)^{b-a} \div(4 a-3 b)^{2 b-a}=(9-8)^{-1} \div(12-6)^1=(1)^{-1} \div(6)^1=1 \div 6=\frac{1}{6}$

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