MCQ
If $A$ and $B$ are disjoint, then $n(A \cup B)$ is equal to
- A$n(A)$
- B$n(B)$
- ✓$n(A) + n(B)$
- D$n(A)\,.\,n(B)$
$n(A \cap B) = 0$
Now $n\,(A \cup B) = n(A) + n(B) - n(A \cap B)$
$ = n(A) + n(B) - 0$$ = n(A) + n(B)$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Class: | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ |
| Frequency | $2$ | $3$ | $x$ | $5$ | $4$ |
is $28$ , then its variance is $........$.