If A and B are independent events, then P(A / B)= ? - Vidyadip

MCQ

If $A$ and $B$ are independent events, then $P(\bar{A} / \bar{B})= ?$

A
$1- P ( A / \bar{B})$
✓
$1 - P(A)$
C
$1 - P(B)$
D
$- P (\bar{A} / B )$

✓

Answer

Correct option: B.

$1 - P(A)$

$P(\overline{A} / \overline{ B })$
$=\frac{P(\bar{A} \cap \bar{B})}{P(\bar{B})}$
$=\frac{P(\bar{A}) P(\bar{B})}{1-P(B)}$
$=1- P ( A )$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Model Paper 2→Model Paper 2 — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The work done by the force $F = 2i - 3j + 2k$ in displacing a particle from the point $(3, 4, 5) $ to the point $(1, 2, 3) $ is ............ $\mathrm{unit}$

The solution of the differential equation $(x - {y^2}x)dx = (y - {x^2}y)dy$ is

if $x$ lies in the interval $[0, 1],$ then the least value of $x^2 + x + 1$ is :

The area included between the parabolas $y^2 = 4x$ and $x^2 = 4y$ is $($in square units$)$

If $\sin\Big(\sin^{-1}\frac{1}{5}+\cos^{-1}\text{x}\Big)=1,$ then the value of $x$ is:

If $ \overrightarrow{ a }=2 \hat{ i }+\hat{ j }+3 \hat{ k }, \overrightarrow{ b }=3 \hat{ i }+3 \hat{ j }+\hat{ k } $ and $\overrightarrow{ c }= c _{1} \hat{ i }+ c _{2} \hat{ j }+ c _{3} \hat{ k }$ are coplanar vectors and $\overrightarrow{ a } \cdot \overrightarrow{ c }=5, \overrightarrow{ b } \perp \overrightarrow{ c }$, then $122\left( c _{1}+ c _{2}+ c _{3}\right)$ is equal to.......

Find the area of bounded by $\text{y}=\sin\text{x}$ from $\text{x}=\frac{\pi}{4}$ to $\text{x}=\frac{\pi}{2}:$

Let $f$ and $g$ be real valued functions defined on interval $(-1,1)$ such that $g^{\prime \prime}(x)$ is continuous, $g(0) \neq 0, g^{\prime}(0)=0, g^{\prime \prime}(0) \neq$ 0 , and $f(x)=g(x) \sin x$.

$STATEMENT$ $-1: \lim _{x \rightarrow 0}[g(x) \cot x-g(0) \operatorname{cosec} x]=f^{\prime \prime}(0)$.and

$STATEMENT$ $-2: f^{\prime}(0)=g(0)$.

If $A$ is a singular matrix, then $\text{A (adj A)}$ is a

The function $f(x) = \int\limits_{ - 1}^x {t({e^t} - 1)(t - 1){{(t - 2)}^3}{{(t - 3)}^5}} dt$ has a local minimum at $ x =$ ..........