Question
If A and B are mutually exclusive events, P(A) = 0.35 and P(B) = 0.45, find:
$\text{P}(\text{A}\cap\text{B}')$

Answer

Since, it is given that, A and B are matually exclusive events.
$\therefore\ \text{P}(\text{A}\cap\text{B})=0$ $[\because\ \text{A}\cap\text{B}=\phi]$
$\text{P}(\text{A}\cap\text{B}')=\text{P(A)}-\text{P}(\text{A}\cap\text{B})$
$=0.35-0$
$=0.35$

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