If A and B are two events such that $\text{P(A)}=\frac{4}{5},$ and $\text{P}(\text{A}\cap\text{B})=\frac{7}{10},$ then P(B|A) =
  • A$\frac{1}{10}$
  • B$\frac{1}{8}$
  • C$\frac{7}{8}$
  • D$\frac{17}{20}$
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