Question
If A and B are two sets such that n(A) = 20, n(B) = 25 and $\text{n(A}\cup\text{B)}=40,$ then write $\text{n(A}\cap\text{B)}.$

Answer

$\text{n(A}\cup\text{B)}=\text{n(A) + n(B) - n(A}\cap\text{B)}$
$\text{n(A}\cap\text{B)}=\text{n(A) + n(B) - n(A}\cup\text{B)}$
$=20+25-40$
$=5.$

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